Trigonometry question

$$\text{Given that } A=\frac{\sin6^{\circ}}{\cos18^\circ} \quad B =\frac{\sin12^{\circ}}{\cos36^\circ} \quad C=\frac{\sin18^{\circ}}{\cos54^\circ} \text{ and }P=\tan18^\circ\cos12^\circ-\sin12^\circ \quad Q=\tan36^\circ\cos24^\circ-\sin24^\circ \\ \quad R=\tan54^\circ\cos36^\circ+\sin36^\circ \text{ then find the value of }\\ \\ N=\left( \frac{A}{P}+\frac{B}{Q}+\left\lfloor \frac{C}{R} \right\rfloor \right)^2+\left\lfloor \frac{A}{P}+\frac{B}{Q}+\left\lfloor \frac{C}{R} \right\rfloor \right\rfloor$$